<\/span>L\u00f4 C\u00e2m L\u00e0 G\u00ec?<\/strong><\/h2>\nL\u00f4 c\u00e2m ch\u00ednh l\u00e0 nh\u1eefng con s\u1ed1 kh\u00f4ng n\u1ed5 trong ng\u00e0y. <\/span>Theo t\u00ean th\u01b0\u1eddng g\u1ecdi m\u00e0 ch\u00fang t\u00f4i ph\u00e2n ra 2 lo\u1ea1i l\u00f4 c\u00e2m: L\u00f4 C\u00e2m \u0110\u1ea7u v\u00e0 L\u00f4 C\u00e2m \u0110u\u00f4i.<\/span>
\nTr\u01b0\u1edbc khi x\u00e1c \u0111\u1ecbnh \u0111\u00e2u l\u00e0 l\u00f4 c\u00e2m th\u00ec c\u00e1c b\u1ea1n c\u1ea7n nh\u1ea5t ph\u1ea3i x\u00e1c \u0111\u1ecbnh \u0111\u00f3 l\u00e0 \u0111\u1ea7u hay \u0111u\u00f4i l\u00f4 c\u1ee7a m\u1ed9t gi\u1ea3i. <\/span>\u0110\u1ec3 d\u1ec5 hi\u1ec3u h\u01a1n, ch\u00fang ta l\u1ea5y v\u00ed d\u1ee5:<\/span>
\nGi\u1ea3i 1 trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 h\u00f4m nay c\u00f3 03679. Nh\u00ecn v\u00e0o 2 con s\u1ed1 cu\u1ed1i c\u00f9ng l\u00e0 79. L\u00f4 h\u00f4m nay v\u1ec1 79, v\u1eady 7 l\u00e0 \u0111\u1ea7u l\u00f4, 9 l\u00e0 \u0111u\u00f4i (\u0111\u00edt) l\u00f4.<\/span><\/p>\n
\nTr\u01b0\u1edbc khi x\u00e1c \u0111\u1ecbnh \u0111\u00e2u l\u00e0 l\u00f4 c\u00e2m th\u00ec c\u00e1c b\u1ea1n c\u1ea7n nh\u1ea5t ph\u1ea3i x\u00e1c \u0111\u1ecbnh \u0111\u00f3 l\u00e0 \u0111\u1ea7u hay \u0111u\u00f4i l\u00f4 c\u1ee7a m\u1ed9t gi\u1ea3i. <\/span>\u0110\u1ec3 d\u1ec5 hi\u1ec3u h\u01a1n, ch\u00fang ta l\u1ea5y v\u00ed d\u1ee5:<\/span>
\nGi\u1ea3i 1 trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 h\u00f4m nay c\u00f3 03679. Nh\u00ecn v\u00e0o 2 con s\u1ed1 cu\u1ed1i c\u00f9ng l\u00e0 79. L\u00f4 h\u00f4m nay v\u1ec1 79, v\u1eady 7 l\u00e0 \u0111\u1ea7u l\u00f4, 9 l\u00e0 \u0111u\u00f4i (\u0111\u00edt) l\u00f4.<\/span><\/p>\n